Question
A camera lens $(n=1.50)$ is coated with a thin layer of magnesium fluoride $(n=1.38) .$ The purpose of the coating is to allow all the light to be transmitted by canceling out reflected light. What is the minimum thickness of the coating necessary to cancel out reflected visible light of wavelength $550 \mathrm{nm} ?$
Step 1
Step 1: We know that the minimum possible thickness can be calculated from the formula $2d = (m + \frac{1}{2}) \lambda$, where $\lambda$ can be written as $\lambda_0/n_{MgF}$ according to the given question. Show more…
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A non-reflective coating of magnesium fluoride (n=1.38) covers the glass (n=1.52) of a camera lens. Assuming that the coating prevents reflection of yellow-green light (wavelength in vacuum = 565 nm), determine the minimum nonzero thickness that the coating can have.
A nonreflective coating of magnesium fluoride $(n=1.38)$ covers the glass $(n=1.52)$ of a camera lens. Assuming that the coating prevents reflection of yellow-green light (wavelength in vacuum $=565 \mathrm{nm}$ ), determine the minimum nonzero thickness that the coating can have.
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