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A capacitor is charged to a potential of 12.0 $\mathrm{V}$ and is then connected to a voltmeter having an internal resistance of 3.40 $\mathrm{M\Omega} .$ After a time of 4.00 $\mathrm{s}$ the voltmeter reads 3.0 $\mathrm{V}$ What are (a) the capacitance and (b) the time constant of the circuit?

a) $8.49 \times 10^{-7} \mathrm{F}$b) 2.89 $\mathrm{s}$

Physics 102 Electricity and Magnetism

Chapter 19

Current, Resistance, and Direct-Current Circuit

Electric Charge and Electric Field

Gauss's Law

Electric Potential

Capacitance and Dielectrics

Current, Resistance, and Electromotive Force

Direct-Current Circuits

Electromagnetic Induction

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