00:01
Hey guys, so to solve this problem, i first written out all of the information that we get from the problem.
00:08
So our frequency is 440 hertz.
00:11
Our voltage is 24 and the change in current is 0 .18.
00:20
So the problem asks us to find the capacitance of the second capacitor.
00:26
So the first thing that we're going to do is find the current of the two capacitors using the equation i sub 1 equals vrms 2 pi fc1, which is for a single capacitor.
00:57
And then we're going to use the equation for both capacitors in combination, which is.
01:34
So as you can see, the only difference in these two equations is this part, and we just have two values for c added together because it's a combination.
01:47
So we are combining that variable.
01:53
So now what we're going to do is take i combination minus i, 1, because we're basically doing the difference, because that difference in current was both minus just the one...