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A car accelerates at $2.0 \mathrm{m} / \mathrm{s}^{2}$ along a straight road. It passes two marks that are $30 \mathrm{m}$ apart at times $t=4.0 \mathrm{s}$ and $t=5.0 \mathrm{s}$ What was the car's velocity at $t=0$ s?

$21 \mathrm{m} / \mathrm{s}$

Physics 101 Mechanics

Chapter 2

Kinematics in One Dimension

Motion Along a Straight Line

Motion in 2d or 3d

Newton's Laws of Motion

Rutgers, The State University of New Jersey

Simon Fraser University

Hope College

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using AIG was two meters per second squared. This has traveled in four seconds, is given by and let's say, velocity at time T equals zero. It was V. He was four second. That displacement is V times for thus half is Ron Times four Square and X times five. It was the displacement after five seconds is three times five, just five squared, So we have 30 meter equals x five minus X four It was 25 dust, five fee minus 16 plus for V equals nine plus V. So we're after Time equals zero is given by week was 31. That's nine. It was 21 meter for a second.

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