a-car-accelerates-at-20-mathrmm-mathrms2-along-a-straight-road-it-passes-two-marks-that-are-30-mathr

Name: a car accelerates at 20 mathrmm mathrms2 along a straight road it passes two marks that are 30 mathr
Uploaded: 2020-06-21
Duration: 1 min 34 s
Channel: Numerade
Description: A car accelerates at $2.0 \mathrm{m} / \mathrm{s}^{2}$ along a straight road. It passes two marks that are $30 \mathrm{m}$ apart at times $t=4.0 \mathrm{s}$ and $t=5.0 \mathrm{s}$ What was the car's velocity at $t=0$ s?

Question

A car accelerates at $2.0 \mathrm{m} / \mathrm{s}^{2}$ along a straight road. It passes two marks that are $30 \mathrm{m}$ apart at times $t=4.0 \mathrm{s}$ and $t=5.0 \mathrm{s}$ What was the car's velocity at $t=0$ s?

Mayukh Banik · Accepted Answer

using AIG was two meters per second squared. This has traveled in four seconds, is given by and let&#x27;s say, velocity at time T equals zero. It was V. He was four second. That displacement is V times for thus half is Ron Times four Square and X times five. It was the displacement after five seconds is three times five, just five squared, So we have 30 meter equals x five minus X four It was 25 dust, five fee minus 16 plus for V equals nine plus V. So we&#x27;re after Time equals zero is given by week was 31. That&#x27;s nine. It was 21 meter for a second.

Johnny Greavu · Answer

we were given that the car&#x27;s velocity as a function of time represented by the following equation. B zero point eight six zero meters per second cube times. He swears. Now we want to find the acceleration the car when he&#x27;s twelve. What&#x27;s that vehicle? Twelve. It&#x27;s for teeth and he is a square root throw. Goodbye point eight six. Oh, therefore he significant figures three point seven seconds. But again, we want to find the acceleration. Now we figured out how long it takes, but the car has to start from rest and accelerate up to twelve meters per second. We found that that it&#x27;s three point seven seconds and we know that the acceleration are the average acceleration that simply the change in velocity with time for the final lost reminds initial velocity Biding my time. Final velocity Here&#x27;s twelve. Our initial is zero sir, from rest time three point seven seconds that we just found. We&#x27;re going on this end and we get twelve divided by three point seven just three point two meters per second squared

Zulfiqar Ali · Answer

the position of the car didn&#x27;t stand. It is defined from the fixed point and the fixed point is a there is s is equal to zero using the position or part. Coordinate. Uh, yes. The EC solution is to be determined A t o b. So X relation is determined is to be determined it be when s is equal to 100 m and X is equal to zero, right? Well, to determine the X relation components tangent to lax relation musical to we don&#x27;t and normal X relation Normal X relation is equal to B squared divided by role Well, ladies first necessity to form weight Uh, we and we don&#x27;t so that they may be people Wait, it&#x27;d be it Point B since the car increases its speed at a constant rate of suit a 0.0.5 meters per second square. So dancing to relax relations equal to 0.5 me to her for a second square. Then they&#x27;ve lost two of the car. When passing be, uh which is eight s is equal to 100 b. Turner can be obtained using the equation. Ah, we be square is equal to we a square artless do times our dandan chillax relation into, uh, SB position of B minus position off a right. So realizing beat we A is equal to 20 m per second. When this is equal to zero, then we have ah, we be square. We be square is equal to 20 square pless two into 0.5 into 100 minus zero. So we be screened musical to 500 meter square for second square All right, well, the card spot is defined by why is equal to 16 minus one, divided by 625 x square, then divided by the by D X is equal to minus two, divided by 625 picks and d square. Why divided by D. X clear is equal to minus two, divided by 625 minus studi body by 625 Right then the radius off richer off to park it be it be when x is equal Prosciutto is given by So robi is given by one bliss de by divided by r D X old square Ah, tree by two divided by Are these great line D squared? Why divided by are the X square, which is equal to one bliss minus two, divided by 625 x whole square to the power through divided by do divided by, uh minus two. Divided by 625. Andi, you let this eight x is equal to zero, then roll and B is equal to 312.5 meter, right? No. Huh? Ex relation. It be so normal. X relation B is equal to the square. Be divided by robi physical too. 500 m square for second square, divided by 312.5 which is equal to 1.6. Me too per second square and total x relation or um, no, we see did before calculating total X religion your point b so tangential x relation it point B is equal to tangential x relation. Uh, sorry, it&#x27;s Yeah, tangential x relation. It point B is equal to tangential X relation. Right? See which is equal to 0.5 meter per second square and the magnitude of the cars Exploration at point B is given by so a b physical to root 0.5 ah square less 1.6 square, which is equal to 1.68 meteor where seconds

Zachary Warner · Answer

we were given an expression for the velocity in the ex direction As a function of tea, Time V of X t, we&#x27;re told, is equal to 0.860 meters per second cube times The time t squared and they were asked to find the evil loss or the acceleration A when the velocity V of X is equal to 12 meters per second. So the first thing I&#x27;m gonna do is plug 12 meters per second into our expression from the velocity and the ex Direction is a function of time and solve for the time variable. So now once I know time, I can use that to calculate the acceleration. So looking at this expression, we see that T squared is equal to zero. Um, excuse me, It&#x27;s equal to V of X, divided by 0.860 meters per second cubed So we take the square root of both sides. We get rid of that square term and we find that T is equal to the square root of V of X, divided by zero point a six year old meters per second cube. So he plugged 12 meters per second in for R V of X value, and we see that tea here is equal to three 0.73 seconds. So now, now that we know that time when V of X is equal to 12 meters per second, we consult for the acceleration. The reason this is true because the acceleration in the ex direction is equal to the time derivative of the velocity and extraction. So the derivative of V of X, Um with respect ity when we do this, uh, that, uh, two term comes down front from the T square term. We have two times 0.860 meters per second cube when we lost the T Square. Now it&#x27;s just tea because the two came down from Okay, So now we completed our 3.73 seconds and for tea, we find that the acceleration here is equal to six point for two meters per second squared. Linkenbach said it is our solution to the question

Surjit Tewari · Answer

question will be using the pasta question off motion. Final velocity is equal to initial lost a plus X elation into time. The final velocity is given this a meter parts again Initially last case by meters per second Ex elation A 0.75 m per second This fire into the time Purity Solving this We will get the time period T 24 seconds.

Abhishek Jana · Answer

so we can use the following equation Tau, find out the final velocity. So here V f is the final velocity, the eyes, the initial velocity and is the ex Elation X is the distance traveled? So we&#x27;re given the initial velocity, which is 10 meters for a second. And there&#x27;s a square plus twice off ax elation which is poor meters per second squared and the distance is 100 meters. So combining this we get defined velocity as 30 meet us per second. So that&#x27;s option Hey!

Problem

Santa loses his footing and slides down a frictio…

Problem 54 Medium Difficulty

A car accelerates at $2.0 \mathrm{m} / \mathrm{s}^{2}$ along a straight road. It passes two marks that are $30 \mathrm{m}$ apart at times $t=4.0 \mathrm{s}$ and $t=5.0 \mathrm{s}$ What was the car's velocity at $t=0$ s?

Answer

$21 \mathrm{m} / \mathrm{s}$

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