00:01
Okay, so in this scenario we're told we have a car and a truck traveling both at the same speed limit of 60 kilometers per hour but in opposite directions.
00:08
The truck has twice the mass of the car.
00:11
So we can call the car's mass m1, the truck's mass would be 2m1, double the size.
00:17
Now, the vehicles collide head -on and become entangled.
00:21
During this collision, how do the forces exerted by each other compare? so, if we take a look, we know we can use the equation f equals ma, right? so in this case, let's take a look at the forces exerted by each of the vehicles.
00:36
So f equals m1a would be the force exerted by the car and then the force exerted by the truck would be 2m1a because we know that really it's m2, but m2 is 2 times the size of m1.
00:56
So it's gonna be double the force.
00:58
So we know that the truck is gonna exert more force on the car than the car will exert on the force.
01:04
Okay, in what direction will the entangled vehicles move after the collision or will they be stationary? so they will not be stationary and the direction they will move will be the motion that the truck had to begin with, right? and we can double check that using our momentum equations, our conservation of momentum.
01:22
We know that m1v1 plus m2v2 is equal to the combined mass of m1 plus m2 times v3, which we'll call the velocity of the entangled collision, if you will, after they've come together.
01:41
Now we know that m2 is 2m1 and we know that v is 60 and v2 is negative 60 so we can express this as 60m1 minus, right, because m2 is 2m and v is negative 60, so minus 2 times negative 60 is equal to 3m1v3.
02:10
Okay.
02:12
We know that all the m's will cancel out and we're gonna get 60 minus 2 times 60, which is negative 60 and negative 60 is equal to 3v3, dividing by 3, v3 equals negative 20 kilometers per hour.
02:32
So this is negative because we've just decided that the car's vehicle speed was positive...