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A car is driven for $2.0 \mathrm{h}$ at $40.0 \mathrm{km} / \mathrm{h},$ then for another $2.0 \mathrm{h}$ at $60.0 \mathrm{km} / \mathrm{h}$ in the same direction. a. What is the car's average velocity? b. What is the car's average velocity if it is driven $1.0 \times 10^{2} \mathrm{km}$ at each of the two speeds?

(a) $50 \mathrm{km}$(b) $48 \mathrm{km}$

Physics 101 Mechanics

Chapter 3

Accelerated Motion

Section 3

Free Fall

Motion Along a Straight Line

Motion in 2d or 3d

Newton's Laws of Motion

University of Washington

Hope College

McMaster University

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the cars. Average velocity is even by total distance traveled, divided by total time taken. Which is we want Do you want us veto d do over the Want us to do now? The speedy's 40 get on with our 40 times two does 60 times two. These are on the unit off kilometer, par our times Our divided by the time is two plus two I wonder so it comes out to be the average velocity 50 kilometer by our well for part B, it seems like, Are you on equals feeding? So using this formula, we can write that the average equals we want t one. Thus very juan. Do you do over the want dusty too, So they steps out to be view on. So if the car travels at same velocity the two intervals then the average velocity is the same

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