a-car-is-speeding-up-and-has-an-instantaneous-velocity-of-10-mathrmm-mathrms-in-the-x-direction-when

Question

A car is speeding up and has an instantaneous velocity of $1.0 \mathrm{m} / \mathrm{s}$ in the $+x$ -direction when a stopwatch reads $10.0 \mathrm{s} .$ It has a constant acceleration of $2.0 \mathrm{m} / \mathrm{s}^{2}$ in the $+x$ -direction. (a) What change in speed occurs between $t=10.0 \mathrm{s}$ and $t=12.0 \mathrm{s} ?(\mathrm{b})$ What is the speed when the stopwatch reads $12.0 \mathrm{s} ?$

Bryce Samwel · Accepted Answer

Okay, First, let&#x27;s write what we know. We know that our initial velocity when it&#x27;s measured at time, equals 10 seconds was one meter per second. And we also know that the car has a constant acceleration and that acceleration is equal to two meters per second squared. So for part A to calculate the change in speed, we&#x27;re going to need the acceleration times, the change in time. So what is the change in time? Well, about the tea for this problem since we&#x27;re going from 12 seconds to 10 seconds is the final minus. Initial times just two seconds. So using the numbers that we have here, we can say tell Ta VI or part A is equal to that two meters per second squared times our change in time, which is two seconds. It gives us a change in velocity of four meters per second. Okay, how for part B, What is the final speed? Well, the final speed for part B is equal to the initial speed, plus the change in the speed. So if we started at one meter per second and added four meters per second, our final answer is five meters per second

Abhishek Jana · Answer

so we can use the following equation Tau, find out the final velocity. So here V f is the final velocity, the eyes, the initial velocity and is the ex Elation X is the distance traveled? So we&#x27;re given the initial velocity, which is 10 meters for a second. And there&#x27;s a square plus twice off ax elation which is poor meters per second squared and the distance is 100 meters. So combining this we get defined velocity as 30 meet us per second. So that&#x27;s option Hey!

Mayukh Banik · Answer

using AIG was two meters per second squared. This has traveled in four seconds, is given by and let&#x27;s say, velocity at time T equals zero. It was V. He was four second. That displacement is V times for thus half is Ron Times four Square and X times five. It was the displacement after five seconds is three times five, just five squared, So we have 30 meter equals x five minus X four It was 25 dust, five fee minus 16 plus for V equals nine plus V. So we&#x27;re after Time equals zero is given by week was 31. That&#x27;s nine. It was 21 meter for a second.

Nicholas Majtenyi · Answer

All right, Question 54. Okay. Asks determined the acceleration of the car in which the velocity changes from minus 10 to minus 20 seconds meters per second. Excuse me in four seconds, party determined the car&#x27;s acceleration, but it changes the minus 22 miles 18 meters per second in two seconds. And explain this This why the sign in each of these two are different. Okay. Province near a growing from 10 meters per 2nd 28 meters per second. All negative. So you know that we can use the equation. Velocity equals the initial velocity plus 18. So I don&#x27;t know the sign of a zombie. Leave it as positive for now. Where for your rearranged equation To be a B minus B not over too. You need 20 minus made 10 on our numerator divided by four seconds. We find the celebration in this part of the question is native to 0.5 meters per second squared. So we&#x27;ll talk about what these what&#x27;s happening? Each integration during party. But for now, let&#x27;s compute them and simply use the same equation for part B again getting my peoples the Overby not over tea, you know, from native. 18. So you&#x27;re from NATO 22 to get 18. So here we&#x27;re adding minus negative. Excuse me. My designated 20 over two seconds and we find to make celebration in this case, his positive 1.0 meters per second squared and party asks, Why are these two sides is different? Well, in part A so that print me, our velocity is changing. If this is a positive direction, then we&#x27;re going from, um bossy. Negative 10 to negative 20. It&#x27;s our celebration will point from our 10 minus 10 years for 2nd 2 on minus 20 meters per second. So we&#x27;re accelerating in the negative direction. Sometimes with this is what this says and in a heartbeat again, if this zero we&#x27;re going from minus 22 minus 18 so exciting in the positive direction to going from it. More native value to a less thing of value. Sort of a cell running towards Nero essentially

Johnny Greavu · Answer

we were given that the car&#x27;s velocity as a function of time represented by the following equation. B zero point eight six zero meters per second cube times. He swears. Now we want to find the acceleration the car when he&#x27;s twelve. What&#x27;s that vehicle? Twelve. It&#x27;s for teeth and he is a square root throw. Goodbye point eight six. Oh, therefore he significant figures three point seven seconds. But again, we want to find the acceleration. Now we figured out how long it takes, but the car has to start from rest and accelerate up to twelve meters per second. We found that that it&#x27;s three point seven seconds and we know that the acceleration are the average acceleration that simply the change in velocity with time for the final lost reminds initial velocity Biding my time. Final velocity Here&#x27;s twelve. Our initial is zero sir, from rest time three point seven seconds that we just found. We&#x27;re going on this end and we get twelve divided by three point seven just three point two meters per second squared

Averell Hause · Answer

so for party to find the acceleration. This would be the final velocity minus the initial velocity divided by Delta T. And so this would be equaling 24.0 meters per second, minus zero divided by two point 95 seconds. And this is giving us 8.14 meters per second squared. So this would be your answer for card, eh? For part B, then Ah, we know that then the required time would be equaling velocity final minus velocity initial divided by a and so this would be equaling 20.0 meters per second, minus 10 0.0 meters per second, divided by a 0.14 meters per second squared. And this is giving us 1.23 seconds for the required time for part B and for part C. Ah, the question is asking us. Will doubling the time always double the change in speed and that&#x27;s yes. We can say that when acceleration is constant, velocity is a linear function. Two time or we can say velocity is directly proportional to time. So essentially doubling the time will double the change in the velocity. That is the end of the solution. Thank you for watching

Problem

You are driving your car along a country road at …

Problem 37 Medium Difficulty

Answer

(a) $\Delta v=4 \mathrm{m} / \mathrm{s}$
(b) $v_{f}=5 \mathrm{m} / \mathrm{s}$

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(a) $\Delta v=4 \mathrm{m} / \mathrm{s}$(b) $v_{f}=5 \mathrm{m} / \mathrm{s}$

Physics

Andy C.

Zachary M.

Jared E.

Meghan M.

Math Review - Intro

Algebra - Example 1

Alan Giambattista, Betty McCarthy Richardson, Robert C. RichardsonPhysics

Andy C.

Zachary M.

Jared E.

Meghan M.

(a) $\Delta v=4 \mathrm{m} / \mathrm{s}$
(b) $v_{f}=5 \mathrm{m} / \mathrm{s}$

Alan Giambattista, Betty McCarthy Richardson, Robert C. Richardson

Physics