A car is traveling at $20.0 \mathrm{~m} / \mathrm{s}$ when the driver slams on the brakes and brings it to a straight-line stop in $4.2 \mathrm{~s}$. What is the magnitude of its average acceleration?
The defining scalar equation is $a_{a v}=\left(v_{f}-v_{i}\right) / t$. Note that the final speed is zero. Here the initial speed is greater than the final speed, so we can expect the acceleration to be negative:
$$a_{a v}=\frac{0.0 \mathrm{~m} / \mathrm{s}-20.0 \mathrm{~m} / \mathrm{s}}{4.2 \mathrm{~s}}=-4.76 \mathrm{~m} / \mathrm{s}^{2}$$
Because the time is provided with only two significant figures, the answer is $-4.8 \mathrm{~m} / \mathrm{s}^{2}$.