A car is traveling due west at 20.0 m / s. Find the velocity of the car after 37.00 s if its c

Name: Problem 4, Chapter 2: University Physics with Modern Physics
Uploaded: 2021-07-26T02:46:39-08:00
Duration: 1 min 50 s
Channel: Shelby Mohamed
Description: A car is traveling due west at 20.0 m / s. Find the velocity of the car after 37.00 s if its constant acceleration is 1.0 m / s^2 due east. Assume the acceleration remains constant. a) 17.0 m / s west b) 17.0 m / s east c) 23.0 m / s west d) 23.0 m / s east e) 11.0 m / s south

step 1 Hello. In this problem, we have a car that is moving with velocity of 20 meters per second, and

Question

A car is traveling due west at $20.0 \mathrm{~m} / \mathrm{s}$. Find the velocity of the car after $37.00 \mathrm{~s}$ if its constant acceleration is $1.0 \mathrm{~m} / \mathrm{s}^{2}$ due east. Assume the acceleration remains constant. a) $17.0 \mathrm{~m} / \mathrm{s}$ west b) $17.0 \mathrm{~m} / \mathrm{s}$ east c) $23.0 \mathrm{~m} / \mathrm{s}$ west d) $23.0 \mathrm{~m} / \mathrm{s}$ east e) $11.0 \mathrm{~m} / \mathrm{s}$ south

   A car is traveling due west at $20.0 \mathrm{~m} / \mathrm{s}$. Find the velocity of the car after $37.00 \mathrm{~s}$ if its constant acceleration is $1.0 \mathrm{~m} / \mathrm{s}^{2}$ due east. Assume the acceleration remains constant.
a) $17.0 \mathrm{~m} / \mathrm{s}$ west
b) $17.0 \mathrm{~m} / \mathrm{s}$ east
c) $23.0 \mathrm{~m} / \mathrm{s}$ west
d) $23.0 \mathrm{~m} / \mathrm{s}$ east
e) $11.0 \mathrm{~m} / \mathrm{s}$ south

University Physics with Modern Physics

Wolfgang Bauer, Gary… 1st Edition

Chapter 2, Problem 4

Instant Answer

Solved by Expert Shelby Mohamed

07/26/2021

Step 1

The car is moving west with a velocity of $20.0 \mathrm{~m} / \mathrm{s}$ and it is accelerating east at a rate of $1.0 \mathrm{~m} / \mathrm{s}^{2}$. We are asked to find the velocity of the car after $37.00 \mathrm{~s}$. Show more…

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A car is traveling due west at $20.0 \mathrm{~m} / \mathrm{s}$. Find the velocity of the car after $37.00 \mathrm{~s}$ if its constant acceleration is $1.0 \mathrm{~m} / \mathrm{s}^{2}$ due east. Assume the acceleration remains constant. a) $17.0 \mathrm{~m} / \mathrm{s}$ west b) $17.0 \mathrm{~m} / \mathrm{s}$ east c) $23.0 \mathrm{~m} / \mathrm{s}$ west d) $23.0 \mathrm{~m} / \mathrm{s}$ east e) $11.0 \mathrm{~m} / \mathrm{s}$ south

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Key Concepts

Kinematic Equations

Kinematic equations are used to relate displacement, initial velocity, final velocity, acceleration, and time in motion problems. When acceleration is constant, these equations, such as the relation v = v0 + at, simplify the analysis of how motion parameters evolve over time.

Vector Quantities and Direction

Velocity and acceleration are vector quantities, meaning they have both magnitude and direction. Understanding the directional aspect is crucial, as the sign (positive or negative) assigned to these quantities depends on the chosen coordinate system, which in turn determines the actual direction of motion.

Uniform Acceleration

Uniform acceleration refers to a constant rate of change of velocity over time. When an object experiences uniform acceleration, its velocity increases or decreases by the same amount each second, allowing the use of simple kinematic equations to determine its motion over time.

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