00:01
For this problem, we have a car that is traveling at 40 meters per second, and it notices something in the road up ahead, and it takes about half a second to react.
00:16
So this car is traveling.
00:18
It travels some distance in that half a second.
00:21
We can figure out what distance that is if we know that that time is 0 .5 seconds.
00:30
So that's our time here.
00:33
We can find the distance using one of our simple formulas for distance with constant velocity.
00:40
That's delta x equals vt, which i wrote in the upper right.
00:45
So delta x equals the 40 meters per second times 0 .5 seconds.
00:58
And we see during this half a second, the car travels 20 meters.
01:08
But then after that time, the car starts slowing down, and it has an acceleration of negative 4 meters per second squared.
01:24
So real quickly here, we can see that it will take the car 10 seconds to slow to a stop.
01:31
And we can find that if we look at the velocity, or sorry, yeah, the velocity divided by the acceleration to get the time it takes.
01:42
Takes to slow to a stop.
01:48
Now we take the absolute value of this, and that gives us 10 seconds...