Question
A car must be driven a distance of $120.0 \mathrm{km}$ in 2.5 h. During the first 1.5 h the average speed was $70 \mathrm{km} \mathrm{h}^{-1}$. What must the average speed for the remainder of the journey be?
Step 1
5 hours. We know that distance is equal to speed times time. So, the distance covered in the first 1.5 hours is given by: \[AB = v_1 \times t_1 = 70 \, \text{km/h} \times 1.5 \, \text{h} = 105 \, \text{km}\] Show more…
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