Download the App!

Get 24/7 study help with the Numerade app for iOS and Android! Enter your email for an invite.

A car starts rolling down a $1-\mathrm{in}-4$ hill $(1-\mathrm{in}-4$ means that foreach 4 $\mathrm{m}$ traveled along the road, the elevation change is1 $\mathrm{m} ) .$ How fast is it going when it reaches the bottom aftertraveling 55 $\mathrm{m}$ ? (a) Ignore friction. (b) Assume an effectivecoefficient of friction equal to $0.10 .$

Get the answer to your homework problem.

Try Numerade free for 7 days

Like

Report

a. $v= 16.41 \mathrm{m} / \mathrm{s}$b. $v=12.8 \mathrm{6m} / \mathrm{s}$

Physics 101 Mechanics

Chapter 5

Using Newton's Laws: Friction, Circular Motion, Drag Forces

Motion Along a Straight Line

Motion in 2d or 3d

Newton's Laws of Motion

Applying Newton's Laws

Rotation of Rigid Bodies

Dynamics of Rotational Motion

Equilibrium and Elasticity

Monafe Y.

November 7, 2020

Cornell University

University of Michigan - Ann Arbor

Simon Fraser University

University of Sheffield

Lectures

02:34

In physics, a rigid body is an object that is not deformed by the stress of external forces. The term "rigid body" is used in the context of classical mechanics, where it refers to a body that has no degrees of freedom and is completely described by its position and the forces applied to it. A rigid body is a special case of a solid body, and is one type of spatial body. The term "rigid body" is also used in the context of continuum mechanics, where it refers to a solid body that is deformed by external forces, but does not change in volume. In continuum mechanics, a rigid body is a continuous body that has no internal degrees of freedom. The term "rigid body" is also used in the context of quantum mechanics, where it refers to a body that cannot be squeezed into a smaller volume without changing its shape.

02:21

In physics, rotational dynamics is the study of the kinematics and kinetics of rotational motion, the motion of rigid bodies, and the about axes of the body. It can be divided into the study of torque and the study of angular velocity.

04:50

A car starts rolling down …

04:16

03:32

04:20

A 400 kg car moving at 20 …

02:44

A car is going at a speed …

18:33

The friction coefficient b…

05:47

A car is traveling down a …

11:14

(a) How high a hill can a …

03:05

(a) How high a hill can a…

08:54

A car drives around a curv…

01:16

A car is driving on a flat…

02:52

A car is coasting without …

02:01

01:22

A car is parked at the top…

in this problem. We are on a one in four hill, meaning that for every four meters traveled along the hill, the elevation changes by one meter. So if we travel 55 meters down the hill, that means the hill is going to be 13.75 meters tall looking. Use this information to sell for the angle, so we continue that science data equals opposite over hypothesis. So 13.75 divided by 55 Give us an angle of about 14 from four degrees, and that will be helpful, helpful for this next part. So we can start by during the three body very grand and this is dissolved for part A, which is with no friction. We have my normal force. We have my force of gravity. We have a component of gravity that goes into the incline old mg cosign vita. And then we have a component of gravity that is down the incline, which is MG science. By using Newton's second love in the X direction, which we're calling down the room, we can see that MG science data is equal again for this, but we have no so using that as our acceleration, making his cannot equation to solve for speed that we have at the bottom of this incline. Assuming you started at arrest from the very top, My final velocity is the square root two wives 98 by the sign of 14. Or eat close the distance. He traveled down the ramp, which was 50. When we get a velocity of about 16.41 or a part B, we're not going back, including friction in our diagram. So going back to everybody diagram, I'm going to have friction that goes up the room. And this is not a fortune. Since it is a movie, it's a party we can say that are some of the forces in the ex direction now, dude friction. So that's MG find data minus friction equals on me. But our action in this case are coefficient of friction. Arms are normal course now. My normal force in this case happens to be equals. MG costar data because it's not accelerating in the my direction or perpendicular. So my normal force is MG Coast. Here, my mess canceled in the life of an acceleration of G science data. But this new plan G people say the uses of democratic equation I would like two times deeds signed a 14 or eight minus our coefficient of friction. Given the problem s 0.1 coastline 40 40 times purposes. I'm 50 by There are this is down the room gives us a farm the velocity of 12.86 which makes sense if it's lowered to now. Frictions. We're not moving, it's fax after.

View More Answers From This Book

Find Another Textbook

11:05

'6_ A block of mass m1 = 2.00 kg and a block of mass mz M, R M1 6.00 kg…

02:55

"II: Speed of Soundsound wave in helium gas: A sound wave travels i…

02:22

'26) A 4.50-kg wheel that is 34.5 cm in diameter rotates through an ang…

03:15

'The coefficient of static friction is 0 60 between the two blocks in t…

05:46

'A liquid flowing from a vertical pipe has a very definite shape as it …

02:30

'10. A light ray of given wavelength; initially in air, strikes a 909 p…

'A uniform ladder of length € and weight mg = 50 N rests against a smoo…

04:32

'9. (II) Three vectors are shown in Fig 3-35. Their magnitudes are give…

03:56

'An automobile initially traveling at 50 km/hr crashes into a stationar…

'43. ssm The greatest height reported for ajump into an airbag is 99.4 …