0 \mathrm{~m/s}$, the acceleration $a = -1.2 \mathrm{~m/s^2}$ (negative because it is deceleration), and the time $t = 3.0 \mathrm{~s}$. We can use the equation of motion $s = ut + \frac{1}{2}at^2$ to find the distance travelled in 3 seconds. Substituting the given
Show more…