Question
A car travels in the $+x$-direction on a straight and level road. For the first 4.00 s of its motion, the average velocity of the car is $v_{av-x}$ = 6.25 m/s. How far does the car travel in 4.00 s?
Step 1
Step 1: Compute displacement using average velocity: Δx = v_{av-x} * Δt. Show more…
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A car travels in the $+x$ -direction on a straight and level road. For the first $4.00 \mathrm{~s}$ of its motion, the average velocity of the car is $v_{\text {ave }}=6.25 \mathrm{~m} / \mathrm{s}$. How far does the car travel in $4.00 \mathrm{~s} ?$
A car travels in the +x-direction on a straight and level road. For the first 4.00 s of its motion, the average velocity of the car is vav?x = 6.25 m/s. How far does the car travel in 4.00 s?
a car travels in the +x-direction on a straight level road. for the first 4.00s of its motion, the average velocity of the car is Vav-x =6.25 m/s. how far does the car travel in 4.00 sec?
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