A car weighing 12,500 N starts from rest and accelerates to 83.0 km / h in 5.00 s. The friction

Name: Problem 46, Chapter 5: University Physics Volume 1
Uploaded: 2023-05-11T05:21:20-08:00
Duration: 2 min 41 s
Channel: Supratim Pal
Description: A car weighing 12,500 N starts from rest and accelerates to 83.0 km / h in 5.00 s. The friction force is 1350 N. Find the applied force produced by the engine.

step 1 Hello and welcome to this video solution of numerate. Here it's given that the weight of the car

Question

A car weighing 12,500 N starts from rest and accelerates to $83.0 \mathrm{km} / \mathrm{h}$ in $5.00 \mathrm{s}$. The friction force is 1350 N. Find the applied force produced by the engine.

   A car weighing 12,500 N starts from rest and accelerates to $83.0 \mathrm{km} / \mathrm{h}$ in $5.00 \mathrm{s}$. The friction force is 1350 N. Find the applied force produced by the engine.

University Physics Volume 1

Samuel J. Ling, Jeff… 1st Edition

Chapter 5, Problem 46

Instant Answer

Solved by Expert Supratim Pal

05/11/2023

Step 1

We know that weight is the product of mass and gravity. So, we can find the mass of the car by dividing the weight by the acceleration due to gravity (9.8 m/s²). \[ m = \frac{W}{g} = \frac{12500}{9.8} \] Show more…

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A car weighing 12,500 N starts from rest and accelerates to $83.0 \mathrm{km} / \mathrm{h}$ in $5.00 \mathrm{s}$. The friction force is 1350 N. Find the applied force produced by the engine.

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Key Concepts

Newton's Second Law

This law states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration (F = ma). It is fundamental in understanding how forces produce changes in an object's motion, and it is used to relate the engine's applied force, acceleration, and the opposing forces such as friction.

Kinematics and Unit Conversion

Kinematics deals with the motion of objects and includes calculating acceleration from changes in velocity over time. Unit conversion is key in these problems, such as converting speeds given in kilometers per hour to meters per second, ensuring consistency in the units used in equations.

Friction Force

Friction is a resistive force that opposes the relative motion between surfaces in contact. In problems like these, the friction force must be taken into account when calculating the net force, as it partially counteracts the applied force and affects the acceleration of the object.

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