00:01
For this question, we have to realize that e is going to be, the efficiency is going to be equal to work divided by qh.
00:07
Now, qh is the amount of energy that goes into the engine, all right? and work is the sort of power output of this engine.
00:14
Okay, so we know work, and we were trying to solve for qh.
00:17
So in order to solve for qh, we must know e, the efficiency.
00:21
Luckily, we know this is a carnot engine.
00:24
Okay, and since this is a carnot engine, we know that it's sort of the maximum thermal efficiency scenario okay and we know that the maximum thermal efficiency is going to be equal to th -t h minus t -c divided by t -h the temperature of the hot reservoir minus the temperature of the cold reservoir divided by the temperature of the hot reservoir however we must do this in kelvin okay so let's convert our t -h and t -c into kelvin by simply adding 273 so we'll get t -h is equal to 500 plus 273 to give us 773 kelvin and same thing for tc it'll be equal to 20 plus 273 giving us a temperature of 293 kelvin okay so now let's plug this our kelvin temperatures into our efficiency equation to get 773 minus 293 divided by 773 to give us an efficiency of about 0 .62 okay now we know our e now, and we know our work, right? that's the amount of energy in one hour.
01:35
So actually, we technically have to calculate that first...