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A Carnot engine whose high-temperature reservoir is at620 $\mathrm{K}$ takes in 550 $\mathrm{J}$ of heat at this temperature in each cycleand gives up 335 $\mathrm{J}$ to the low-temperature reservoir. (a) How much mechanical work does the engine perform during eachcycle? (b) What is the temperature of the low-temperaturereservoir' (c) What is the thermal efficiency of the cycle"
(a) $W=215 \mathrm{J}$(b) $T_{C}=378 \mathrm{K}$(c) ecarnot $=39 \%$
Physics 101 Mechanics
Chapter 16
The Second Law of Thermodynamics
Temperature and Heat
Thermal Properties of Matter
The First Law of Thermodynamics
Cornell University
University of Michigan - Ann Arbor
Simon Fraser University
McMaster University
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but told the cardinal engine, whose high temperature reservoir is at 620 Calvin takes and 550 tools of heat at this temperature and each cycle, and gives up 335 jewels to the low temperature reservoir. First, we want to know how much mechanical work does the engine performed during the cycle we're giving our high temperature are heat in and are out. We know that the work output is just the heat and minus the heat out. That gives us 215. Jules. They want to know what is the temperature of the low temperature reservoir. But we have the relationship between the heat in and heat out and the temperatures and so minus the heat out divided by the N equals minus the ratio of the temperature of the cold to the temperature of the hot. And so the temperature of the cold reservoir equals. They eat out, divided by the heat and divided by the temperature of the times, the temperature of their hot reservoir Fucking in our numbers, we get 378 Calvin and finally, why I know what is the thermal efficiency of the cycle well for carnal cycle. We could get the thermal efficiency if we know the temperatures of the reservoirs. And so the in fresh and sea is just one minus the ratio of the cold reservoir to the temperature of the hot reservoir plugging in our numbers, we get 0.39 or 39%.
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