a-cars-velocity-increases-from-40-to-50-kmh-in-10-s-what-is-its-acceleration

Name: a cars velocity increases from 40 to 50 kmh in 10 s what is its acceleration
Uploaded: 2019-08-30
Duration: 4 min 2 s
Channel: Numerade
Description: A car’s velocity increases from 40 to 50 km/h in 10 s. What is its acceleration?

Question

A car’s velocity increases from 40 to 50 km/h in 10 s. What is its acceleration?

Kara Merfeld · Accepted Answer

right. So, amigo, acceleration is basically how fast something speed changes. So the equation for that is acceleration is the change in velocity over a change in time. And basically, we just have to plug in the things that we know. So this is Ah, the ending velocity or the velocity of time too minus starting velocity or the velocity of time. One divided by how much time that takes. So he said it was 50 a za smiles or kilometers kilometers 50 um, kilometers per hour. 00 Um oh, uh, minus 40 kilometers per hour. It happens in 10 seconds. Okay, so basically, we have 50 minus forties, 10 kilometers per hour per 10 seconds. Sophie, subtract all that out. We have our first RV. It&#x27;s attract 44 50 in the dry, but 10 we&#x27;re left with one kilometer Kurt per hour per second. If we were to put this in more standard units, we could do some dimensional. Alice is to put this in either kilometers per hour squared or kilometers per second squared. Oh, and I guess we should probably do that. So in order to do that. So this this here what? We have is a perfectly correct answer, but we could make it more conventional by changing some units around. So we can either change the seconds in powers or the hours into seconds. And when we do, that is say, okay, we multiply it by, um, Roy, I totally didn&#x27;t mean to make that line right there. We can multiply it by, um, the fact that every hour has 3000 600 seconds per one. Our what we&#x27;re doing, we multiply this number, we can do that. And the reason we can do that is because 3600 seconds is equal to one hour. So we&#x27;re really just multiplying by one. And then we have here. You have a cancellation. You can see that this seconds on top. Cancel It cancels with this seconds on bottom, and we can multiply that out. And this is then, um, 36 100 uh, kilometers per hour per hour. Work per hour. No. Started me to write that. Cross you there or per hour. Squirt

Katelyn Chen · Answer

So we were asked to determine the acceleration of a car to increase from 30 MPH to 50 MPH in the given time of five seconds. So to start off with, we know that a couple pieces relation with other time it&#x27;s equal to flush. We know that vo zero, which is equal to 30 MPH we&#x27;re also gonna be five is equal to 50 MPH. And we know that the conversion. So we&#x27;re we got a conversion from seconds hours. So we have five seconds. Nursery 1006 100 is equal to 1/7 20 hours. It is. How long for seconds are the first falling on the anti our acceleration using unknown. So it&#x27;s eight. So they saw with that information. You know that beauty. Is he going to 80 plus c Now we also know that be a five nice via zero. You go to 80 plus see Notice a time, Cerrell. My honesty. So we can plug in our information that we know 50 my 30 a times T minus zero. And so we have 20. You go to a and our time is one over Some 120 hours, which we talked earlier. So based off of this information, we know that a is equal to 20 time 720 which is equal to 14,400 MPH squared. Now we want to cover just two feet per seconds. Word So we have a is equal to 14 400 times 5000 Children, 80 over 3600 squared three per second squared, which is equal to approximately 5.87 feet per second squared. That&#x27;s acceleration. It required to go from 30 MPH to 50 MPH in five seconds.

Mayukh Banik · Answer

acceleration is given by the final miners we insure over the time taken, which is 36 minus four meter for a second divided by four second. So that&#x27;s 30 do over four is eight meters per second squared.

Ernest Castorena · Answer

So this time they tell us a car is undergoing celebration. So our acceleration is const. And after four seconds, it is accelerated from 30 miles an hour into 50. So do U minus three report. That&#x27;s just 20/4, which is just five sellers. Acceleration will be increasing by five MPH every second. Let&#x27;s see. So they want to know how much the car has traveled during those three seconds. Well, we know that our velocity, let&#x27;s see, is equal. Teoh starting at 30 and adding five every additional second. So we&#x27;re gonna need to take the position function, and we can take the position at the last second. Subtract the position that sex Teoh what we want. Well, let&#x27;s see the anti derivative. This is fine. He squared over two plus 30 plus some another. See? Okay, whenever we want to know the difference in positions as a sorry 19 seconds. So when we do s for attract s zero will be subtracting this unknown constant from itself. So it&#x27;s gonna cancel out. It&#x27;s irrelevant to us here, So let&#x27;s just plug in for and we&#x27;ll get let&#x27;s see. Five time 16 over to laws 30 times for the track bull zero plus zero. So let&#x27;s complete this. This isn&#x27;t AIDS, so we have 40 plus 1 20 1 60 You can assume that they&#x27;ve traveled the 1 60 miles.

Bobby Barnes · Answer

well, so if we want to increase the speed of this car from 30 to 50 miles in five seconds after 30 MPH to 50 MPH in five seconds, the first thing I would do is get all the by units in the same measurement, because knows, here we have miles. And but then time here we&#x27;re having in seconds. So just to kind of make things a little bit easier, I&#x27;m going to convert this two hours. So to do that, we would need to divide despite 3. 60. So it be five or not. 30. 60 3000, 600. So five divided by 3600. That would simplify down to 1/72. So I&#x27;m just gonna leave it like that for right now, So this is ours. So now what we can do is since acceleration is just constant well, we know that acceleration is supposed to be the derivative of our time. I mean, the derivative of our velocity with respect to time. And so this is just a constant. We ask ourselves. Well, the anti derivative of this is going to be some function that we take the derivative it we just get a constant and well, that&#x27;s going to be a of T. And then we would just add some arbitrary constant to this. Uh huh. And so now if we were to come over here and plug in T is equal to zero, we could solve for what see is because then that&#x27;s going to tell us our velocity should be 30. So we have 30 is equal to so eight times zero is just zero, and then it just c So C is 30. So we have our velocity being a T plus 30. So now we just need to figure out Well, what is, um is supposed to be And we can use that using the fact that we know at five seconds or one over 720 hours, the velocity should be 50. So let&#x27;s go ahead and write that so t equal to one over 720 philosophy should be 50. So we plugged that in. So 50 is equal to s 05 times a plus 30. I&#x27;m sorry. Not five, um, one over 720. So now we can go ahead, subtract So it be 20 is able to one over 728. Multiply that over. Um, so 7, 20 times 20 14,400 is our acceleration. And now remember the unit with this. So our time was in miles. I&#x27;m sorry, are distance is in miles and our time is in ours. So this is going to be MPH squared. Um, so that is one way to think about it. But normally we think of accelerations in terms of like, feet per second squared. Least we&#x27;re going to be doing it in these units. So why don&#x27;t we go in and convert that to the here also, So we have 18,000 MPH squared, so we would need to cancel out miles. So for every one mile, there is 5280 ft, and then the hours will need to cancel that out twice. So for one hour, there is going to be 3600 seconds and then one hour, 3600 seconds. So these units cancel out with each other. The miles cancel also that we just multiply straight across and then divide. So we multiply the numerator, and we get some huge number that we divide that by 3600 twice, and that gives 88/15 feet per second squared, which is approximately 5.87 So this here is going to be. And actually, you could have also used this one up here. So either one of these, Um, the important thing is that you actually write your units down with this, because otherwise, all right, it&#x27;s kind of vastly different numbers, but as long as you have your units than it should be fine.

Shital Rijal · Answer

Okay, So the question is asking, what is the acceleration of a car that moves at the student velocity off 100 times per hour? So for how many signals? 100 seconds. Assertion is actually the chains in velocity with respect to time. Right. So in this in not even one second even in power in 100 seconds, there is no chance Adversity in this case here. Indeed he is. Zero right. This implies that there is no change in velocity, so exercise is also equal to zero. My So this is access. And so the Russian wants us to expend this answer. So we can&#x27;t just say that if velocity is constant, the velocity is gone. Standard time with giant two, there is neighbor all Mom, zero acceleration. Okay, so this ends the solution to the school.

Problem

What is the acceleration of a car that maintains …

Problem 9 Medium Difficulty

A car’s velocity increases from 40 to 50 km/h in 10 s. What is its acceleration?

Answer

2.78 $\mathrm{m} / \mathrm{s}^{2}$

Related Courses

Conceptual Physics

Related Topics

Discussion

Top Physics 101 Mechanics Educators

Elyse G.

Liev B.

Marshall S.

Zachary M.

Physics 101 Mechanics Courses

Math Review - Intro

Algebra - Example 1

Recommended Videos

Watch More Solved Questions in Chapter 3

Video Transcript

Paul G. Hewitt

Conceptual Physics

Elyse G.

Liev B.

Marshall S.

Zachary M.

Math Review - Intro

Algebra - Example 1

What do you need help with?

Textbooks

Ask a question

Courses

AI Tutor

2.78 $\mathrm{m} / \mathrm{s}^{2}$

Conceptual Physics

Elyse G.

Liev B.

Marshall S.

Zachary M.

Math Review - Intro

Algebra - Example 1

Paul G. HewittConceptual Physics

Elyse G.

Liev B.

Marshall S.

Zachary M.

Paul G. Hewitt

Conceptual Physics