00:01
For this problem, we are told that a cashier has a total of 30 bills made up of ones, fives, and 20s.
00:07
The number of 20s is nine more than the number of ones.
00:10
The total value is $351, and we are asked how much of each denomination are there.
00:16
So this one problem actually is describing a system of equations, even though it's not quite obvious.
00:21
There's the number of ones, the number of fives, the number of 20s.
00:25
Those will be our three unknowns, and we are given three equations.
00:28
So, we know that a plus b plus c, where let's say that a is the number of ones, actually i'll be a little bit more concrete, let's call it o's, f's, and t's, ones, fives, and 20s.
00:47
We know that o plus f plus t is going to equal 30.
00:53
We know that t, the number of 20s, is nine more than the number of ones.
00:59
So t is going to equal o plus 9.
01:04
You have that the total value is $351.
01:08
So that means that o plus 5 times f plus 20 times t equals 351.
01:20
So the second equation, we can plug directly into the first equation and get an expression relating o and t directly, or rather o and f directly.
01:33
So we'd have that o is going to equal, or rather, o plus f plus o plus o plus 9.
01:43
I'll put a little curl in my o to make sure that it doesn't look like a zero.
01:49
So we have o plus f plus o plus 9 is equal to 30...