00:01
So we're told that a catalyst is a substance that either accelerates a chemical reaction or is necessary a chemical for the reaction to occur.
00:08
So say suppose we have an enzyme e, which is a catalyst, combines with a substrate s, a reacting chemical to form an intermediate product x and then produces a product p and releases the enzyme.
00:23
If initially there are x not moles per liter of s and there is no p, then based on the theory of michaelis and meton, the concentration of p, which is a function of time, after t hours is given by this.
00:42
And what are all these variables in here? well, v is the maximum possible speed of the reaction.
00:51
K is a constant.
00:53
And then we told the x not is the initial number of moles of s.
00:57
So we're basically going, so we have an enzyme, the same, the same, the same, the same, the we're trying to get the, there's a product p and releases in.
01:06
So we're trying to get, what am we trying to do here? e is the catalyst.
01:12
S is the substrate to a reacting chemical to form an intermediate product x and then produce s or a p and releases the enzyme.
01:27
So basically, i guess the substrate is reacting with something.
01:31
I don't know what it is, but we're forming something.
01:35
The substrate reacts with the catalyst, and then that thing reacts for something else, and releases the enzyme, so then it can, you know, react more, you know, can basically do itself some more, do some more work as a catalyst.
01:52
Anyway, this is the formula.
01:58
Now, they want us to know, where, let's see, what do they want? find the rate of change of the formation of the product p in this reaction.
02:07
Okay.
02:08
So we can explicitly differentiate this thing with respect to time.
02:14
So over here we just get v, so that's an easy one.
02:17
Here, you know, this is just p dot, and now we need to take the time derivative of this.
02:22
So we have our constant k here, we have a minus sign there, and then the derivative of this is one over the argument, so we get that, and then we need to take the derivative of the argument, and that's minus p.
02:33
Dot over x -not...