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A catcher catches a 145 g baseball traveling horizontally at 36.0 $\mathrm{m} / \mathrm{s}$ . (a) How large an impulse does the ball give to the catcher? (b) If the ball takes 20 $\mathrm{ms}$ to stop once it is in contact with the catcher's glove, what average force did the ball exert on the catcher?

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a) 5.22 $\mathrm{kg} \mathrm{m} / \mathrm{s}$b) 261 $\mathrm{N}$

Physics 101 Mechanics

Chapter 8

Momentum

Physics Basics

Kinetic Energy

Potential Energy

Energy Conservation

Moment, Impulse, and Collisions

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June 22, 2021

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That's question. We're told that a baseball with a mass of 0.145 kilograms, or 145 jewels is initially traveling at a speed of 36 meters per second. And over the course of 0.2 seconds, um comes into contact with the catcher's mitt and comes to rest. So, um, let's initially assumed that the ball is moving in the positive X direction. In part, they were asked to find the impulse that the ball applies to the catcher. Um, so first weaken simply finds thean pulse that the catcher place to the ball, which is easy to do because impulse is just equal to, um, the change in momentum. So, um, for the ball, um, the ball initially has a momentum of, um, mass times its initial velocity. And at the end of this collision, it has a momentum of zero. And I just need to write that all down, um, so plugging in the constants that were given the impulse, um, applied by the catcher to the ball is, um, negative 0.145 kilograms times 36 meters per second. So the impulse of the ball, and I'll specify that here, JB for impulsive the ball words just plain J is the impulse of the player. The impulse of the ball is plugging this into a calculator. Negative 5.22 kilogram meters per second. Um, now, since momentum is conserved in this collision, the impulse applied by the player to the bow, um, is equal and opposite toothy impulse applied by the ball to the player. So we just need to multiply this by negative 12 finds that the impulse, um, imparted by the bolt the player is 5.22 kilogram meters per second. Now, um, in part, that's the answer to part A in part B. Um, we need to find the average force that the ball exerted on the player over the course of this collision. And to do this, we just need to remember that impulse is equal to the average force over some length of time, divided by the length of that time. So we're given both these constant so just need to rearrange to solve for F, so it's equal to impulse times, the type, the length of time, and that's equal to substituting in the Constance 5.22 kilogram meters per seconds multiplied by 0.2 seconds. Plugging this into a calculator, we find that the force is 261 mutants. That's the answer to party.

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