a-cereal-flake-is-burned-under-a-beaker-containing-25-mathrmml-of-water-if-the-water-temperature-goe

Name: a cereal flake is burned under a beaker containing 25 mathrmml of water if the water temperature goe
Uploaded: 2020-10-18
Duration: 1 min 2 s
Channel: Numerade
Description: A cereal flake is burned under a beaker containing 25 $\mathrm{mL}$ of water. If the water temperature goes up $6^{\circ} \mathrm{C}$ , how many calories of energy were transferred to the water?

Question

A cereal flake is burned under a beaker containing 25 $\mathrm{mL}$ of water. If the water temperature goes up $6^{\circ} \mathrm{C}$ , how many calories of energy were transferred to the water?

David Collins · Accepted Answer

Question five is a pretty straightforward calculation. One thing that you need to consider is the density of water. If we have 25 mL of water, this means we have 25 g of water. This is important so that we can use the specific heat of water in order to calculate the calories of energy that were transferred to the water by the cereal. Flake que then will be equal to the specific heat of water. One calorie per gram degree Celsius multiplied by the mass of the water, 25 g multiplied by the change in temperature. It increased six degrees Celsius. This then gives us the calorie content of heat transferred to the water by the cereal flake. 150 calories.

Bin Chen · Answer

Okay. So for this question, they want us to determine how much heat is needed to raise the temperature off the water from 25.52 degrees Celsius to 28.75 And they give us the volume as 50 milliliters and the density of H 20 as 200.997 grams familiar. So the first thing that we should do is we should convert the volume of water, two grams of water, right? The reason why is because eventually the equation that we&#x27;re gonna need to solve this question is Q is equal to see which is a specifically constant of that substance. Times of by mass in grams and then times by Delta T. Right, So we need mass. So we can do is we know the volume and we know the identity. So we can use these two values to solve for mass So mass of water massive H 20 is you go to density divided by the volume, right, cause we know density way. No density is massive outed by volume. So if we were to multiply both sides by volume, we get massive legal to density times volume and that&#x27;s exactly what we&#x27;re doing here. So massive a show is equal to DNC, which is 0.997 grams familiar times of by the volume, which is 50 milliliters. So I&#x27;m leaving milliliters the volume of milliliters, because the density has milliliters. Right? So we get the massive H 20 as mass is equal to 49.85 grams. Right? We have Gramps now, so we know this this value we look in our textbook and we or we can look online and we should these just see that&#x27;s ah specific key capacity specific heat capacity of H 20 physical to 4.184 Jules for Graham Times. Kelvin. Right. So we see that this constant has Grams, Jules and Calvin. So let&#x27;s convert these temperatures into Calvin&#x27;s. All right, we know that the mere races we know that the convergent between Celsius and Calvin is 273 right? So it&#x27;s at 273 to d Celsius. To get Kelvin eso 40 I we should get to 98.52 Kelvin and for T final, we should get 301.75 come in. Now let&#x27;s plug in everything into this equation. So cue physical to see which is 4.18 Ford George put grams of Kelvin times by M we found to be 49.85 49.85 grams times about the Delta T Delta T is the There&#x27;s a go to temperature final minus temperature initials. So we have to remember its temperature Final minus initial can&#x27;t be initial minus final. So we get 3/1 0.75 K minus 298.52 K And, uh, we accused go to 4.184 jewels grams Kelvin for 9.85 grams and this is equal to three points to three. Calvin eso uh, the reason why I wrote this expression again down here, it&#x27;s that I was just poking this one into calculators because I want to show you how the units work, Right? So we have grams on the top. So Granville correct cancels out Grams Kelvin on the top. Coming will cancel out Kelvin and we&#x27;re left with jewels. Right? So we put this into the calculated would get Q is equal to 673.7. And what is the unit of Cuba? We see that we only have jewels left, right? So the units of Q must be jewels, and this is the answer.

Kristela Garcia · Answer

this problem asks us to calculate the energy required to raise the temperature of 200 grams of water from 20 degrees Celsius to 30 degrees Celsius for the specific heat capacity. See use one calorie her graham degree Celsius so we can use the equation. Q equals M cat as it&#x27;s normally referred to. Where m is the mess, See is a specific heat and delta T is the change in temperature. So our masses 200 Gramps are specific. Heat is one calorie per gram degree Celsius, and our change in temperature is always final minus initial. So this is our final temperature minus our initial temperature gives us a energy of 2000 calories.

Shital Rijal · Answer

with so many kind of rays have needed, it seems to imprison a fun to watch her body one. Okay, uh, one gram off lodger. Bye. One degree census. So this is basically asking us the specific huge capacity off water. And that is, of course, one calorie program for digger senses. Right? So we can say one calorie alfyed is required now to melt one gram off ice subzero degree. So this is James, or increase. This is merit. Made one gram off eyes, one gram off eyes, uh, one gram of ice Ingenuity recesses. So this is basically asking us on the Latin heat off Susan, right? Major monogram of ice and the resources to off course water. Navy&#x27;s really senses. So that is like me. Love Susan on that is 80 calories our grand. So the heat require is 80 calorie. Now, the next is their price. No VIP. Arise One gram off. Watcher It, Jeter. Did you census Well, what right, gamble. So you it 100 usages. So that is basically asking us the Latin He docked preparation. And that is why I wondered. And 40 calories. Yes, we are done. This question

Ricajoy Montero · Answer

your problem. 81 um, were given the sample of water, which is 7 25 grams. And we&#x27;re told that, um the temperature lowered from 65 degrees sauces to 37 degrees sauces and then, um were asked to calculate the heat and killer jewels. So, um, this is actually pretty straightforward. Would be equals two EMC Delta T. Okay, So l&#x27;m would be your Massey would be your specific heat for water and delta T would be your change in temperature. So in this case, we know that water lost heat because it got colder. So that change in temperature, we don&#x27;t care as much about the about. The sign is we&#x27;re just getting the difference. So the difference between 65 37 stick or calculators used if I, minus 37 goes to study eight. Okay, so our differences 28 The grease Sasha&#x27;s. So let&#x27;s go ahead and calculate. Right, So the mass of water is 7 25 grams 7 25 grams. I multiply it with the specific heat of water, which is 4.184 Jules for Graham degree, Sasha&#x27;s. And though the tea or change in temperature the difference is done. A degree sauces. OK, so given that we cancel the grams, the council, the degree sauces and all that&#x27;s left versus the convert this, Jules, and to kill a jewels. So one killed Jewel is 1000 jewels, so we get to cancel that as well. Okay, so stake our calculator. Here. I got 7 25 times, 4.184 Oops. Shown to any fire times for 0.1 it or times 28. And we divide that by 1000. So 89 point nine. 89 or sorry. 84.9. Set that aside. 84.9 kilo jewels, and that&#x27;s your final answer.

Zachary Warner · Answer

or question says that, uh, assume that the ocean water enters a suit at 10 degrees and is warmed by the divers skin temperature of 35 degrees. So the change delta T is 25 degrees, and it wants us to estimate how much energy is required by this heating process. So the total surface area of the wetsuit is one meter squared and it has a thickness d of 0.5 millimeters or 0.5 times, 10 to the minus three meters. We&#x27;re also going to use the density of water row of 1.2 for 1025 kilograms per meter. Cute. So, uh, we can use that to find the mass and then use the fact that one killer calorie of energy raises one kilogram of water by one degree Celsius that the water warms by 25 degrees Celsius right from 10 to 35. So the volume here is equal to the area times the thickness right, which is equal to the mass divided by the density row. Therefore, the mass is equal to row times the volume with just the area times a thickness d, which comes out to be 0.5125 in units of course, of mass or kilograms. Okay, so now that we know that we can convert this into the change of temperature of this mass so mass times delta t into kilocalories by using the conversion factor that one kill a calorie converts one kilogram by one degree Celsius. So degree Celsius. All those haven&#x27;t implied one in front of them. So plugging the value for massively just calculated as blows the value for Delta T. This comes out to equal 12.8 kilocalories. But we were asked to put this not killer calories, but in bars. Well, we were also told that for every one bar there is 300 kilocalories. So there&#x27;s our conversion and bars carrying this out. We find that this is equal toe zero 0.0 for three bars. Weakened box set in as a solution to the question

Problem

Fuel pellets are used in modern energy-saving woo…

Problem 5 Easy Difficulty

A cereal flake is burned under a beaker containing 25 $\mathrm{mL}$ of water. If the water temperature goes up $6^{\circ} \mathrm{C}$ , how many calories of energy were transferred to the water?

Answer

150 cal

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