Download the App!

Get 24/7 study help with the Numerade app for iOS and Android! Enter your email for an invite.

. A certain cannon with a fixed angle of projection has a range of 1500 $\mathrm{m}$ . What will be its range if you add more powder so that the initial speed of the cannonball is tripled?

Get the answer to your homework problem.

Try Numerade free for 7 days

Like

Report

13500 $\mathrm{m}$

Physics 101 Mechanics

Chapter 3

Motion in a Plane

Physics Basics

Motion Along a Straight Line

Motion in 2d or 3d

Newton's Laws of Motion

Abdul R.

March 22, 2022

Range of cannon is 1.5 km when angle of projection is 15°. Then the max range of the cannon is:

Rutgers, The State University of New Jersey

University of Washington

University of Sheffield

Lectures

03:28

Newton's Laws of Motion are three physical laws that, laid the foundation for classical mechanics. They describe the relationship between a body and the forces acting upon it, and its motion in response to those forces. These three laws have been expressed in several ways, over nearly three centuries, and can be summarised as follows: In his 1687 "Philosophiæ Naturalis Principia Mathematica" ("Mathematical Principles of Natural Philosophy"), Isaac Newton set out three laws of motion. The first law defines the force F, the second law defines the mass m, and the third law defines the acceleration a. The first law states that if the net force acting upon a body is zero, its velocity will not change; the second law states that the acceleration of a body is proportional to the net force acting upon it, and the third law states that for every action there is an equal and opposite reaction.

04:16

In mathematics, a proof is a sequence of statements given to explain how a conclusion is derived from premises known or assumed to be true. The proof attempts to demonstrate that the conclusion is a logical consequence of the premises, and is one of the most important goals of mathematics.

02:59

A cannon fires a cannonbal…

02:08

"A bullet is fired fr…

06:33

A cannon with a muzzle spe…

0:00

A rifle is fired with angl…

02:18

A projectile is shot verti…

01:47

A 1000.-kg cannon shoots a…

04:12

A projectile is fired from…

02:31

A projectile is shot from …

02:04

A cannon located at sea le…

So here we're going to triple the initial velocity. So we had me. We're going to assume that they'll tow Y equals zero meters. Therefore, you can use the range equation. This equals the initial squared times sign of tooth Ada divided by G. We're going to assume that fada here is 45 degrees because we're trying to get the maximum range. So our max, we'll simply be equal to the initial squared over G again if they'd a equals 45 degrees, two times 45 degrees would be 90 degrees and sign of 90 degrees would equal one. So 11 times the initial squared would simply be then the initial squared, divided by G. And so we can say that once we have this relationship, we can say that thie maximum range is directly proportional to these squared to the initial velocity squared. So if the final equals three times velocity initial, we can say that our Max final will divided by our max initial is going to be equal to velocity final squared, divided by velocity initial squared. Remember there directly proportional. So you can simply make this. You could make this proportion and let's plug in for VI final. So this would be three the initial squared, divided by the initial squared. And this would equal nine. Which means that our Max final would equal nine times the initial maximum range. And we know the next the initial maximum range to be 1,500 meters. So nine times 1,500 and we're getting 13,500 meters. So this would be the new range if the initial velocity was again tripled. That is the end of the solution. Thank you for watching.

View More Answers From This Book

Find Another Textbook

Numerade Educator