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A certain element has its outermost electron in a 3$p$ subshell. It has valence $+3$ because it has three more electrons than a certain noble gas. What element is it?

Aluminum

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in this exercise have a certain element that has its outermost electron in the third piece of show. And we also have the information that the valence off the elements this plus three meaning that in the last shell that is in the show and equals three, there are three elections. Okay, Uh, so what we need to do is to determine what element this is. So the first thing I'm gonna do is to try to find the electronic configuration. Ah, off this element. So let's go. Let's start to feel all the Aldous of Shells until we get to three p. So we have one s. There are two elections here. Then we have the to acid show which also has two elections. The next sexual is to pee, which fits six elections. The next one is three s, which fits to elections in the last is three p. Now, how many elections should we put here? Well, if the surveillance is plus three, this means that there are three elections in the n equals three shell. Since we already already have two electrons in these assets ships social, we only have to put one extra electric in the piece of shit. Now what we need to do is to some oh, the electrons here. So we have to plus two plus six plus two plus one. So this is 13. So this whatever element this is, it has 13 elections, which means that its atomic number is 13. So now we have to do is to go to a periodic table into look up. Which element has the time number equal to 13. And if you do that, you're going to see that the aluminum has 13. Has the atomic number equal to 13. So this is our answer.

Universidade de Sao Paulo