00:02
So basically when gas is heated at constant p for part a, so as pressure is constant, so our pf would be equal to 10, 5, pa is equal to pi.
00:20
Next one is for part b.
00:24
So we have pf, vf is equals to nrtf.
00:30
So vf will be equal to nrtf divided by pf.
00:38
So we have equal to 2 times 8 .314 times 8 ,400, divided by 10, raised the par 5.
00:48
That would be equal to 0 .66 cubic meter.
00:53
Our final temperature is 400 kelvin for part c, for part d.
01:01
We have to identify our internal energy.
01:05
So that would be equal to n.
01:09
We have t divided by 2 r, delta t, which is equal to 2 times 7 over 2 times 8 .314, 400 minus 300.
01:24
So this would be internal energy is equals to 5 ,819.
01:32
Point 8 joules.
01:35
Next one is for part e.
01:40
So we need to identify our heat is equal to 2 times 9 over 2 times 8 .814 times 400 minus 300.
01:54
That would be equal to negative 1662 .8 joules.
02:00
Next one when gas is heated at constant volume to 400k.
02:05
So we have 4 .662.
02:06
400k.
02:09
So for part a, so here we have pf is equals to 2 times 8 .314 times 400, divide 0 .066 is equals to 1 .33 .13 .33.
02:34
For our final volume, it will be vf, which is equal to v.
02:42
That is equal to 0 .04984 cubic meter.
02:49
For part c, final temperature is still 400 kelvin.
02:54
For part e, our internal energy is 5 ,814 .8 joules, which is the same from the previous one.
03:04
Next one is we have part e for the heat.
03:10
So we have q is equals to 7 over 2 times 2...