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A certain reaction is spontaneous at $72^{\circ} \mathrm{C}$. If the enthalpy change for the reaction is $19 \mathrm{kJ} / \mathrm{mol}$, what is the minimum value of $\Delta S$ (in $\mathrm{J} / \mathrm{K} \cdot \mathrm{mol}$ ) for the reaction?

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$\Delta S>55$ J / K mol.

Chemistry 102

Chapter 17

Entropy, Free Energy, and Equilibrium

Thermodynamics

Sharon R.

March 16, 2021

Ksp for Co(OH)2 at 25°C is 3.3 × 10?16. Using this and data from your textbook, calculate the value of ?G o f for Co(OH)2(s).

Carleton College

University of Maryland - University College

Brown University

Lectures

00:42

In thermodynamics, the zeroth law of thermodynamics states that if two systems are in thermal equilibrium with a third system, they are also in thermal equilibrium with each other.

01:47

A spontaneous process is one in which the total entropy of the universe increases. In a spontaneous process, the system will move from an ordered state to a disordered state, such as from ice to water, or from a solid to a gas. The concept of spontaneity was introduced by Rudolf Clausius in 1850.

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So we have a spontaneous reaction and we know were given that it has a positive entropy change. And so, uh, the entropy has to be making this reaction go on. The question is, Well, how big does Thean trip you have to be? What's its minimum value? So this is much like finding out the temperatures at which a reaction is spontaneous. It's based on the relationship between Delta, G, Delta, H and Delta s. Except in this case of a similar situation in that we're going to set equal to zero, depending on the value of Delta s Delta G. Could be lessons you were greater than zero. If we know the value of Delta s that makes equal to zero, then we can reason what values of Delta s will make it greater than Lucy. Less than zero make it negative. Eso ah, again, we said equal to zero. We subtract Delta H from both sides, but rather than dividing by Delta s or negative Delta's to get t, we divide by negative t to get till toe s so that is Delta H over the temperature. We were given the delta H in the temperature told that it's spontaneous. And so the, uh, entropy change that we calculate is 55.1. And so, uh, basically, delta s has to be greater than ah, 55.1. Jules promote killed in

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