Ask your homework questions to teachers and professors, meet other students, and be entered to win $600 or an Xbox Series X 🎉Join our Discord! Oh no! Our educators are currently working hard solving this question. In the meantime, our AI Tutor recommends this similar expert step-by-step video covering the same topics. Numerade Educator ### Problem 33 Easy Difficulty # A certain telescope has an objective mirror with an aperture diameter of$200 . \mathrm{mm}$and a focal length of$2.00 \times 10^{3} \mathrm{mm} .$It captures the image of a nebula on photographic film at its prime focus with an exposure time of 1.50$\mathrm{min} .\$ To produce the same light energy per unit area on the film, what is the required exposure time to photograph the same nebula with a smaller telescope that has an objective with a 60.0 -mm diameter and a 900 -mm focal length?

#### Topics

Electromagnetic Waves

Wave Optics

### Discussion

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### Video Transcript

{'transcript': "here we have Ted or not equals negative. A prime over. If not so we find that age prime equals negative data, not times two major Now we want equals I not a one equals I know times by our square all he's 0.1 major square of that we have you wan equals B Juan de 30 one. It was, I know by you don't want one meter square times 1.5 I mean it. No. Similarly, we can find Ito equals P to tell 32. It was, I know lives by See the point 03 meter square time still dirty. Do no taking a rescue off that because we have same amount of light energy cummings per unit area. Using that, we can find your 30 do equals. Seen a point, do over 0.6 squares tires. 0.9 over to square times 1.5 minute. It was 3.38 Meaning"}

Indian Institute of Technology Kharagpur

#### Topics

Electromagnetic Waves

Wave Optics