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Problem 33 Hard Difficulty

A chain of nuclear reactions in the Sun’s core converts four protons into a helium nucleus. (a) What is the mass difference between four protons and a helium nucleus? (b) How much energy in MeV is released during the conversion of four protons into a helium nucleus?

Answer

a) $4.6 \times 10^{-29} \mathrm{~kg}$
b) $26 \mathrm{~Mey}$

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Video Transcript

we know that massive proton is about 1.67 to 5, multiplied by 10 to the power minus 27 kilograms. Uh, mall self proton is a cool too. 1.67 two five Multiply by 10 to the power minus 27 kilograms. It's the moss. It was single proton. Now let's to park a well. The difference in the Mosses of the helium ups and the four per tones I can be calculated is, uh four. Multiply by 1.67 25 Multiply by 10 to the power minus 0.7 kilogram. Since we have four per tones minus uh, 6.6 for fuller, multiply by 10 to the power minus 27 killing Pratt and therefore a difference in masses of peculiar ups in four protons. Let's say difference in masses tell Damn! So delta am is equal to 4.6. Multiply by 10 to the power minus 29 kilogram. Let's to part B. Using E is equal to dealt. I am multiplied by C Square, but we have dealt out, which is 4.6. Multiply by 10 to the power minus 29 kilogram multiplied by C. Square and C Square. These nine point Zito multiply by 10 to the power 16 meter square or a second screen, and this gives us four point 14 Multiply by 10 to the power minus 12. Jules, the lips can work. Piece number two Mega electron volts. Well, Reno did. One mega electron walked is equal to 1.602 Multiply by 10 to the power minus 13 Jules and then four up 4.14 Multiply by 10 to the power minus 12. Jules is equal to We have, uh, 4.14 Multiply by 10 to the power minus 12. Maga Electron won't divided by 1.6 zero to multiply by 10 to the power minus 30. And this is a cool too almost 20 six mega electron won't

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