Like

Report

A charge of $1.70 \times 10^{2} \mu \mathrm{C}$ is at the center of a cube of edge 80.0 $\mathrm{cm}$ . No other charges are nearby. (a) Find the flux through the whole surface of the cube. (b) Find the flux

through cach face of the cubc. (c) Would your answers to parts (a) or (b) change if the charge were not at the center? Explain.

The answer to part (b) will change because charge is at different distances from each face of the

cube.

You must be signed in to discuss.

Cornell University

University of Michigan - Ann Arbor

University of Washington

University of Sheffield

Hello, Strengths. Let's start our discussion. Suppose a charge cube off 1.7 into 10 days. Part two micro column is placed inside a center off a cube. Okay, No, we have to find out a total flux as assuming that Asuman get square as a cautions that face. So if we will have the value off flux is enclosed by upside in north and the total child that is enclosed in our go ocean surface that this cube is 1.7 into 10. This part too intact. And this bar minus six cooler by Well, you've absolutely not. Is 8.85 in tow. Tell this par minus 12. Okay, So by solving this, we will get a value off 1.92 in tow. 10 this part. Savin new. Tell me this crap. Coolum. Okay, this is the total for rocks or whether hold you. Now, suppose you have to find out the floods only for one side of the square. Okay, so, basically for six face Oh, for one, face off the cube for six faces the flux Is this Now for one faces for what? If ISS flex will be won by six off total flux. And that will be 3.2 in tow. 10 days by six Newton Meters square. Poor Coolum. Well, this is all from me for this video. I hope you will like the ritual. Thank you.