00:01
In the first part of this problem, we are going to calculate the potential at the origin.
00:06
So we have to calculate this capital v.
00:09
Let's define the potential v equals to k -q1 divided by r1 plus k -q2 divided by r2.
00:25
What's quality equation number 1? now let's calculate r1 and r2.
00:32
R1 is equal to square root of into 3 .0 .55m.
00:45
5 .m .m .2.
00:48
Plus into 4 .50 meter whole square.
00:57
So this will give us the value for r1 as a 5 .440 meter.
01:10
Similarly we can write the expression for r2 as r2 equals to square root of well into minus 2 .533 meter whole square plus into 0 .0.
01:35
So this will give us the value for r2 as 2 .533 meter.
01:44
Now setting values into the given equation number one we can write we equal to we have the value for k and we take it as common 8 .99 multiply weighterase power 9 newton meter square per column square and then we have q1 as minus 2 .505 multiply by eternalized power minus 6 column divided by v.
02:30
F .r1 as 5 .440 meter plus we have q2 as 1 as 1 .875 meters plus we have q2 as 1 .875 multiply by turnerous power again minus 6 column divided by v...