00:01
So for this problem, we have an electric field that's going upward, and it has a magnitude of 4 .00 times 10 to the 4 newtons per coulum.
00:15
And the charge of the charge in the field is 28 times 10 to the minus 9 couloms.
00:28
And our goal is to get the work for a few different paths.
00:31
So for a the path is this.
00:37
It goes to the right.
00:40
Let's see, what does it say? 0 .45 meters to the right.
00:45
And so we want to find the work by the electric force.
00:50
So work is equal to force dotted into displacement.
00:56
And so the force is directed up and then displacement is directed to the right.
01:03
And so because there's no component of the force that's parallel to the displacement, the work is zero.
01:12
And also to be clear, the force is the electric force, and that's going to be this qe.
01:20
So we're dotting the electric field, which is pointing up into the displacement, which is pointing to the right, and then that because they're perpendicular, that's zero.
01:29
Another way to think about it is you could take the cosine of the angle between e and d because you could, it's technically also q, e, d, cosine of the angle between them.
01:42
So here's the angle between them.
01:45
And it's 90 degrees.
01:47
And so that becomes zero.
01:49
And so for b, the path is up the along the electric field.
01:57
And so this time there is a component of the force along the electric, or excuse me, along the displacement...