Question
A charge of $+3.0 \times 10^{-6} \mathrm{C}$ exerts a force of $940 \mathrm{~N}$ on a charge of $+6.0 \times 10^{-6} \mathrm{C}$. How far apart are the charges?
Step 1
The first charge, Q1, is given as $3.0 \times 10^{-6} \mathrm{C}$, the second charge, Q2, is given as $6.0 \times 10^{-6} \mathrm{C}$, and the force of repulsion, F, is given as $940 \mathrm{N}$. Show more…
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