Question
A charged particle $+q$ of mass $m$ is placed at a distance $d$ from another charged particle $-2 q$ of mass $2 m$ in a uniform magnetic field of induction vector $B$ (as shown in figure). If particles are projected towards each other with equal speeds $v_{0}$ the maximum value of the projection speed $v_{0}$, so that the two particles do not collide, is: (Assume only magnetic force of interaction between particles)B(x)(a) $\frac{q B d}{m}$(b) $\frac{q B d}{2 m}$(c) $\frac{2 g B d}{m}$(d) none of these
Step 1
The radius of the circular path can be given by the formula $r = \frac{mv}{qB}$, where $m$ is the mass of the particle, $v$ is the velocity of the particle, $q$ is the charge of the particle and $B$ is the magnetic field. Show more…
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