Question
A chemical system has three particles that can have energies of $0,5,10,15,$ or $20 \mathrm{~J}$. If the total energy of the system is $30 \mathrm{~J}$, how many different ways can the particles be organized?
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The possible combinations are: (0,10,20), (5,5,20), (10,10,10), and (5,10,15). Show more…
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Suppose two systems, each composed of three particles represented by circles, have 30 J of total energy. System A: 10 J There are three balls: blue, red, and green. System B: 12 J There is a red ball. System C 10 J There is a blue ball. System D 8 J There is a green ball. In how many energetically equivalent ways can you distribute the particles in System A? In how many energetically equivalent ways can you distribute the particles in System B?
There are two chemical systems, $A$ and $B$, each with two particles that have a total energy of $20 \mathrm{~J}$. For the first system, the two particles each can have energies of 0,5 , $10,15,$ or $20 \mathrm{~J},$ and for the second system, the particles can have energies of $0,10,$ or $20 \mathrm{~J}$. Which configuration will have the least entropy?
(i) Given 3 distinguishable particles each of which can be in any of 4 states with (different) energies $E_{1}, E_{2}, E_{3}$, and $E_{4}$, (a) what is the total number of ways of distributing the particles amongst the states?, (b) how many states of the system have total energy $E_{1}+E_{2}+E_{4}$ ? (ii) Repeat (i) for 3 electrons instead of distinguishable particles.
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