00:01
In this question, we have a convex spherical mirror with a child holding a candy bar 15 .5 centimeters in front of the convex side.
00:10
The image height is told to be reduced by one half.
00:14
We would like to find the radius of curvature for this mirror.
00:20
To start, we will need to know which equations we should use.
00:26
Since we're calculating the radius of curvature, it will be helpful to have this formula that the focus of a spherical mirror is a equal to negative radius of curvature divided by 2.
00:39
Now we note that we have p, and we can probably calculate q.
00:45
If we have p, q, and f, this tells us to use the lens equation.
00:50
1 over f equals 1 over p plus 1 over q.
00:59
All that is left to do is find q.
01:04
If we find q, then we can use this equation to calculate f, and then this equation to calculate r.
01:15
Notice that i've drawn already the rays, the principal rays for this object and optical setup.
01:24
With this geometry, we see that an image will be formed virtually behind the mirror at approximately this location.
01:33
Notice that this is not drawn to scale.
01:40
Okay.
01:41
Since the image height is reduced by one half, this gives us some additional information about the system.
01:48
Notably, it's magnification.
01:50
The magnification is equal to the ratio of image heights, which we are told is one -half...