00:01
So the diagrams for this problem are shown here.
00:05
So this is the top view and this is the side view.
00:10
So in this problem we have, let's say t is the tension in the stream.
00:18
We need to determine this.
00:32
So from these two diagrams, it is obvious what are the free body diagrams or what are the forces acting on this child? it is the m g acting downwards and the tension t acting along the stream okay so applying newton's law for vertical and horizontal directions we can write for horizontal direction it is t quos theta is equal to m v squared by r where v is the velocity for speed of the child because it will supply the centricatal force.
01:46
So this is for horizontal direction.
01:48
For vertical direction, as you can see from the diagram, so it will be t -syn theta equal to n g.
02:18
Now it is asked that what is the acceleration along the direction.
02:24
So along the y direction as the child is rotating in a horizontal circle, so along the y direction the acceleration will be zero...