00:01
So we're told that a child slides across the floor in a pair of rubber sole shoes.
00:07
We're told that the friction, there's a friction coefficient on each foot, and the force from that friction is 20 newtons.
00:17
The cross -sectional area of each shoe is 14 centimeters squared.
00:23
The thickness of the sole is 5 millimeters, and the shear modulus of the rubber is 3 ,000.
00:30
3 .0 megapascals.
00:33
So what our situation is here is that we have the shoe here and then the rubber sole is here and then there's a sheer stress applied at the base and it causes the sheer deformation of the rubber here.
00:48
And what we want to find out is how far what this distance is here, how much this base shifts over from the top from where it initially was.
01:00
So we can figure out what the sheer stress is down here by taking the force, the total force, and divide it by the area.
01:09
Again, we're assuming that the force is uniformly applied over this whole area so that we have a uniform stress, sheer stress...