00:01
Hi, in the given problem, the value of resistance of the circuit is 175 oom, the capacitance is 4 .50, micro ferret and self -inductance is l is equal to 0 .735 henry.
00:21
Emf light is 5 .0 volt, and the source frequency is 100 hertz.
00:28
So, to find impedance of this circuit, first of all, we find its inductive reactance, which is xl, is equal to 2 pi fl.
00:39
So here this is 2 times of 3 .14, multiplied by frequency, which is 100 hertz, and then self -inductance, which is 0 .735 and re.
00:51
So finally, this inductive reactance here comes out to be 4161 .58 o.
00:58
Now we find its capacity reactance which is 1 by 2 pi fc.
01:04
So plugging in the known values again this is 2 times of 3 .14 multiplied by frequency again which is 100 hertz and then the capacitance which is 4 .50 micro ferret or 4 .50 into 10 rich per minus 6 ferret and finally this capacitive reactance here comes out to be 353 .86 oom.
01:32
So finally, impedance of this circuit will be given by the square root of the square of net reactance, which is xl minus xc here, and square of resistance.
01:46
So plugging in the known values here, here it comes out to be the square root of square of 461.
01:58
58 minus 353 .08.
02:03
.86 to the whole square plus square of its resistance which is 175...