00:01
So we have a sample size of 24, and i calculated the x bar of those numbers to be 24 .375 with a sample standard deviation of 8 .94336.
00:16
And we want to find a 99 % confidence interval for the mean.
00:23
And so we'll take that 24 .375, and we're going to need our t value, which.
00:30
With 23 degrees of freedom, and then that alpha over 2 is going to be all our alpha is 0 .01, so it's going to be .005.
00:41
And 23 degrees of freedom with 0 .005 is corresponding to 2 .807.
00:52
So we'll have plus or minus 2 .807 times the standard deviation, divided by the square root of 24.
01:06
And i believe i just use software, but i'm going to double check that software, that that will be from this value to this value.
01:16
But again, i'm going to type that into my calculator just to be on the safe side, minus 2 .807 times that 8 .94 -336 divided by the square root of 24.
01:33
And i do get this value.
01:35
And if you need one more decimal place, it's 07, so this would round to 1.
01:40
And when i change it to an addition sign, i do get 29 .49...