A coffee-cup calorimeter contains $100.0 \mathrm{mL}$ of $0.300 \mathrm{M}$ HCl at $20.3^{\circ} \mathrm{C} .$ When $1.82 \mathrm{g} \mathrm{Zn}(\mathrm{s})$ is added, the temperature rises to $30.5^{\circ} \mathrm{C}$. What is the heat of reaction per mol Zn? Make the same assumptions as in Example $7-4,$ and also assume that there is no heat lost with the $\mathrm{H}_{2}(\mathrm{g})$ that escapes.
$$\mathrm{Zn}(\mathrm{s})+2 \mathrm{H}^{+}(\mathrm{aq}) \longrightarrow \mathrm{Zn}^{2+}(\mathrm{aq})+\mathrm{H}_{2}(\mathrm{g})$$