0 L of water from 10°C to 100°C.
The specific heat capacity of water is approximately \(4.18 \, \text{J/g°C}\).
First, convert 1.0 L of water to grams:
\[
1.0 \, \text{L} = 1000 \, \text{g}
\]
Next, calculate the temperature change:
\[
\Delta T = 100°C -
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