00:01
In this given problem, first of all, there is a solenoid, a horizontal solenoid, which is having the wire wound over it as given here in this figure.
00:25
It has been wound in this fashion.
00:35
This is the source of emf.
00:39
This is the resistance in the circuit 4 .00 om.
00:45
Then there is a coil, a 15 turn coil, coaxial coil with this solenoid.
01:04
Here it is having 15 turns in all.
01:10
Radius of this coil the bigger coil that has been given as r is equal to 10 .0 centimeter the number of turns total turns in it 15 and for the solenoid the radius is smaller 2 .00 centimeter the number of turns per unit length that is 1000 per meter and current is varying with the time as per the equation 5 .00 ampere the maximum current into sine 120p.
02:03
Therefore magnetic field at the center of the solenoid we know the expression for the magnetic field at the center of the of the solenoid which is mu not n into i so magnetic flux passing through this coil linked through the coil that is given as phi is equal to n b a the total flux that's why number of turns in the coil should be multiplied with it hence using all the expressions, this phi comes out to be n times of mu not, an i into pi r squared...