Question
A coil of wire $0.25 \mathrm{m}$ long and having 400 turns carries a current of $15 \mathrm{A}$.(a) What is the magnitude of the magnetic field strength $H ?$(b) Compute the flux density $B$ if the coil is in a vacuum.(c) Compute the flux density inside a bar of chromium that is positioned within the coil. The susceptibility for chromium is found in Table 20.2.(d) Compute the magnitude of the magnetization $M$.
Step 1
Substituting the given values, we get $H = \frac{400 \cdot 15}{0.25} = 24,000$ A-turns/m. Show more…
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