00:01
In this problem it is said that a coin is tossed four times.
00:04
We have been given two events x and y and we need to find certain probabilities assuming that each of the 16 head tail sequences have the same probability.
00:14
So first of all let us draw a tree diagram to determine the 16 head tail sequences.
00:19
So we toss the coin once it either lands on heads or tails.
00:25
On the second toss it either lands on heads or tails.
00:29
So the second toss heads or tails.
00:33
And then on the third toss it either lands on heads or tails.
00:41
And then on the fourth toss it either lands on heads or tails.
00:52
Now using this tree diagram we can determine the 16 head tail sequences.
00:57
The first one will be h h h h then we'll have h h h t then we'll have h h t h and so on.
01:05
So let's just write down all of those head tail sequences.
01:23
Now we can find the required probabilities.
01:26
So first of all we want to find the probability of x complement intersection y.
01:31
So this will be the number of favorable outcomes divided by the total number of outcomes.
01:35
The total number of outcomes is 16.
01:37
And what will the favorable outcomes be? so we have x complement intersection y.
01:42
Intersection represents and.
01:44
So x is the event that the first and last coins have opposite faces.
01:49
So x complement means that the first and last coins have the same face...