00:01
Hello friends as soon in the figure, a collar with mass 1 kg is rigidly attains to the slender rod av of mass 3 kg and length 600mm that is 0 .6 meter.
00:34
The rod is released from rest that is omega 1 is 0 and v1 is 0.
00:47
We have to find the value of d for which angular velocity of the rod maximum for angular velocity of rod to be maximum at theta to be 90 degree.
01:24
Let us start solving it.
01:27
Horizontal position is initial position for rod.
01:49
Velocity of rod to be omega into l .y2 and for velocity of color, visc equal to d omega for position 1 omega is 0 velocity v1 is 0 hence total kinetic energy would be 0 for position 2 total kinetic energy is half mass of rod into vr square half moment of energy of the rod into omega square there is half mass of the collar into its velocity is square and half mass of the color into its velocity substituting the value, velocity is omega into ly2.
03:41
Moment of inertia of the rod, mrl squared by 12 into omega square by 12 into omega square half.
04:09
Mass of the color into velocity of color is omega into d.
04:16
So this could be written as 1x m r l square omega square plus half...