Question
A collie drags its bed box across a floor by applying a horizontal force of $8.0 \mathrm{~N}$. The kinetic frictional force acting on the box has magnitude $5.0 \mathrm{~N}$. As the box is dragged through $0.70 \mathrm{~m}$ along the way, what are (a) the work done by the collie's applied force and (b) the increase in thermal energy of the bed and floor?
Step 1
In this case, the force is 8.0 N and the distance is 0.70 m. So, the work done by the collie's applied force is: \[ W = F \cdot d = 8.0 \, \text{N} \cdot 0.70 \, \text{m} \] Show more…
Show all steps
Your feedback will help us improve your experience
Keshav Singh and 97 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A collie drags its bed box across a floor by applying a horizontal force of 8.0 $\mathrm{N}$ . The kinetic frictional force acting on the boxhas magnitude 5.0 $\mathrm{N}$ . As the box is dragged through 0.70 $\mathrm{m}$ along the way, what are (a) the work done by the collie's applied force and (b) the increase in thermal energy of the bed and floor?
(a) How much work is done when you push a crate horizontally with 100 $\mathrm{N}$ across a $10-\mathrm{m}$ factory floor? (b) If the force of friction on the crate is a steady 70 $\mathrm{N}$ , show that the KE gained by the crate is 300 $\mathrm{J}$ . (c) Show that 700 $\mathrm{J}$ is turned into heat.
To pull a 50 $\mathrm{kg}$ crate across a horizontal frictionless floor, a worker applies a force of 210 $\mathrm{N}$ , directed $20^{\circ}$ above the horizontal. As the crate moves $3.0 \mathrm{m},$ what work is done on the crate by (a) the worker's force, (b) the gravitational force, and (c) the normal force? (d) What is the total work?
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD