00:01
Hi there, so for this problem, we are given that the reynolds number is equal to the density of the fluid, row, the speed b, d is the inner diameter of the pipe, and eta is the viscosity of the fluid.
00:15
So, for part a of this problem, the question is, less model blood of density that we are given in there, 1 .06, thanks then to the 3, and viscosity as a pure liquid, that is in order to fat that it contains red blood cells, so it's supposed it is flowing in a large artery of radius that we are also given in there, which is 1 .5 centimeters with a speed that is also given.
00:41
So we need to determine that the flow is laminar.
00:46
Okay, so we just need to substitute these values into the expression that we are given, into the reynolds expression, reynolds number expression.
00:56
So the density that we are given for blood is 1 .06 times 10, to the 3, this in units of kilograms per cubic meter, this times the speed that is 6 .7 times 10 to the minus 2.
01:12
This is in units of meters per second.
01:15
Now the diameter is two times the radius that we are given.
01:19
So that will be 3 centimeters.
01:21
That is 3 times 10 to the minus 2 in meters.
01:25
And this divided by the viscosity that we are also given that value, and that value is 3 times 10.
01:31
To the minus 3 in units of pascal times seconds.
01:37
So, simplifying this, using our calculator, we obtain a value of 710.
01:43
Now, since this value is less than 2 ,300, then with that, we can conclude that the flow is laminar.
01:56
So that's the solution for part a of this problem.
02:00
Now, for part b, we are asked about, imagine that the artery ends in a single capillary so that the radius of the artery reduces to a much smaller value.
02:14
What is the radius of the capillary that will cause the flow to become turbulent? so we are going to denote the situation in part 8 using subscripts 1 and in the expression for the reynolds number for the capillary, which we denotate as the situation too.
02:32
So we incorporate the continuity equation for fluids as the red blood flows into the smaller blood vessel.
02:40
So we will have the renal numbers 2 is equal to the density times this speed 2 times the diameter 2.
02:49
This divided by the meal, what we're going to call mu.
03:02
And then this, we can write this as the density times the speed 1.
03:12
This is the area 1 divided by the area 2.
03:15
In here we have used the continuity equation.
03:18
These 2 times the radius that we are given, the radius 2.
03:23
This divided by mu.
03:28
Then, and we know that the area 1 is pi times the radius 1 to the square, and the area 2 is pi times the radius 2 to the square.
03:40
So canceling and simplifying everything, we will find that this is 2, times the density times the speed 1 times the radius 1 and after the square this divided by mu times the radius 2...