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A compound microscope uses a $75.0-\mathrm{mm}$ lens as the objectiveand a $2.0-\mathrm{cm}$ lens as the eyepiece. The specimen will be mounted122 $\mathrm{mm}$ from the objective. Determine (a) the barrel length and(b) the total magnification produced by the microscope.

a) 0.19 $\mathrm{mm}$b) $-32$

Physics 103

Chapter 27

Optical lnstruments

Wave Optics

Rutgers, The State University of New Jersey

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so in this problem is pretty similar to the previous one. So what we have here? We have a specimen place at a distance off 122 millimeters. This is shouldn't be too millimeters. And we know that the focal objective length is seven 0.5. Saying team enters and the focal eyepiece Lance is just two. Same team enters, and the first thing we need to discover is the barrel lens off this microscope. Okay, so first of all, we need to calculate distance off the image through the objective lens and how we do this using the Finland's equation, which is one divided by F objective minus one, divided by he's zero oh, to the power of miners one. So this is just going to be one divided by 75 miners, one divided by 122 all to the power of minors. While this is going to be equal to 0.19 meters, Okay, now that we have the distance off the image and we have the eyepiece, the focal eyepiece left, we know by definition that the barrel ends. Let's call l is just the distance off the image plus the focal eyepiece lens. So the first answer that we need is just 0.19 plus 0.2 just the focal. Why peace? So this is zero point 21 meters. That's the first answer to this problem. The second answer to this problem. The second item we need to calculate. It's Toto magnification. And we know by definition that the total magnification is just miners. The eye times am divided by the focal objective times bifocal eyepiece length. So by standard, we can always tell that the near point is just 25 centimeters. So this is going to be miners. Sorry, that's putting. Same team enters it is a better way to calculate miners 19 times 25 off near point, divided by seven points, five times two. So this is just minus starting to and that's the final answer to this problem. The total magnification is miners dirty, too

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