A compound related to acetylacetone is 1,1,1-trifluoroacetylacetone (abbreviated Htfa):
Htfa forms complexes in a manner similar to acetylacetone. (See Exercise 49.) Both Be $^{2+}$ and $\mathrm{Cu}^{2+}$ form complexes with tfa - having the formula $\mathrm{M}(\mathrm{tfa})_{2}$ . Two isomers are formed for each metal complex.
a. The Be $^{2+}$ complexes are tetrahedral. Draw the two isomers of $\mathrm{Be}(\mathrm{tfa})_{2} .$ What type of isomerism is exhibited by $\mathrm{Be}(\mathrm{tfa})_{2} ?$
b. The $\mathrm{Cu}^{2+}$ complexes are square planar. Draw the two isomers of $\mathrm{Cu}(\mathrm{tfa})_{2} .$ What type of isomerism is exhibited by $\mathrm{Cu}(\mathrm{tfa})_{2} ?$