A compound with molar mass 180.1 g / mol has the following composition by mass: C 40.0

step 1 So we're given the motor mass of a compound and also the mass composition. We're going to find t

A compound with molar mass 180.1 g / mol has the following...

A compound with molar mass $180.1 \mathrm{g} / \mathrm{mol}$ has the following composition by mass:
$$\begin{array}{|ll|}\hline C & 40.0 \% \\H & 6.70 \% \\O & 53.3 \% \\\hline\end{array}$$
Determine the empirical and molecular formulas of the compound.

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Key Concepts

Percentage Composition

This concept involves understanding the mass percentages of each element present in a compound. It is the basis for determining how much of each element is present in a given total mass, which is then used to determine relative amounts in moles.

Conversion from Mass Percentage to Moles

This step involves converting the percentage composition of each element into moles by dividing the mass of each element (derived from the percentage) by its respective atomic mass. This conversion allows for the establishment of a mole ratio among the elements, which is crucial for identifying the simplest ratio of atoms.

Empirical Formula Determination

The empirical formula represents the simplest whole number ratio of the elements in a compound. Once the moles of each element are calculated, they are divided by the smallest number of moles to obtain the simplest ratio, which forms the empirical formula.

Molecular Formula Determination

The molecular formula shows the actual number of atoms of each element in a molecule, which may be a multiple of the empirical formula. To determine the molecular formula, the mass of the empirical formula is compared to the given molar mass of the compound, and a scaling factor is applied to the empirical formula.

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